# PolarPlot and PolarPlot3D in Decibel

I'd appreciate it if someone could help converting my code so that the graph shows value in Decibel, which normally can be easily done using the formula below.  I managed to draw the graph in Amplitude, as shown on the figure above, but when I try to change it into decibel by multiplying it with 10 Log[], the graph shows peaks of infinite decibel values, and became like this: Here is my code, I really hope I can get some help figuring this out.

Clear["Global*"]
a = 3 λ; b = 2 λ;
β = (2 π)/λ; E0 = 1; r = λ/4;
X = (β a)/2 Sin[θ] Cos [ϕ];
Y = (β b)/2 Sin[θ] Sin[ϕ];
Z = I (a b β E0 Exp[-I β r])/(2 π r);
Et[θ_, ϕ_] := √((Z/
2 Sin[ϕ] (1 + Cos[θ]) Sinc[X] Sinc[Y])^2 + (Z/
2 Cos[ϕ] (1 + Cos[θ]) Sinc[X] Sinc[Y])^2);
SphericalPlot3D[
Et[θ, ϕ], {θ, 0, 2  Pi}, {ϕ, 0, 2  Pi},
Mesh -> None, PlotPoints -> 30, PlotRange -> All, Axes -> True,
AxesOrigin -> {0, 0, 0}, PlotStyle -> Directive, Boxed -> False]


Thanks in advance!

• The Log of zero is minus infinity. Therefore, you will not be able to draw directions where Et is small. You could e.g. only draw if Et` is bigger than some threshold. – Daniel Huber Apr 27 at 16:17