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I would like to get a picture of a contour map like this: plot

I tried to modify the following code to remove the filled color on the contour map. So far I didn't succeed.

 contourPotentialPlot1 = ContourPlot[-3600. h^2 + 0.02974 h^4 - 5391.90 s^2 + 
   0.275 h^2 s^2 + 0.125 s^4, {h, -400, 400}, {s, -300, 300}, 
 PlotRange -> {-1.4*10^8, 2*10^7}, Contours -> 15, Axes -> False, 
 PlotPoints -> 30, PlotRangePadding -> 0, Frame -> False, ColorFunction -> "DarkRainbow"];

potential1 = Plot3D[-3600. h^2 + 0.02974 h^4 - 5391.90 s^2 + 0.275 h^2 s^2 + 
    0.125 s^4, {h, -400, 400}, {s, -300, 300}, 
   PlotRange -> {-1.4*10^8, 2*10^7}, ClippingStyle -> None, 
   MeshFunctions -> {#3 &}, Mesh -> 15, MeshStyle -> Opacity[.5], 
   MeshShading -> {{Opacity[.3], Blue}, {Opacity[.8], Orange}}, Lighting -> "Neutral"];

level = -1.2 10^8; gr = Graphics3D[{Texture[contourPotentialPlot1], EdgeForm[], 
Polygon[{{-400, -300, level}, {400, -300, level}, {400, 300, level}, {-400, 300, level}}, 
VertexTextureCoordinates -> {{0, 0}, {1, 0}, {1, 1}, {0, 1}}]}, Lighting -> "Neutral"];

Show[potential1, gr, PlotRange -> All, BoxRatios -> {1, 1, .6}, FaceGrids -> {Back, Left}]

If we run the above code we would get a picture like this: plot

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  • $\begingroup$ You neglected to mention that the pictures came from this answer. Next time, if you are giving code you did not write yourself, please link to the original source. $\endgroup$ – J. M.'s ennui 2 days ago
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ContourShading -> None and remove ColorFunction -> "DarkRainbow"

contourPotentialPlot1 = 
  ContourPlot[-3600. h^2 + 0.02974 h^4 - 5391.90 s^2 + 
    0.275 h^2 s^2 + 0.125 s^4, {h, -400, 400}, {s, -300, 300}, 
   PlotRange -> {-1.4*10^8, 2*10^7}, Contours -> 15, Axes -> False, 
   PlotPoints -> 30, PlotRangePadding -> 0, Frame -> False, 
   ContourShading -> None];
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    $\begingroup$ Thanks alot. It works. $\endgroup$ – Hana 2 days ago

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