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Below, is it possible to print No and have x be 2. That is, I'm looking for an And-like function that looks at all arguments before returning.

x := 1
If[And[True, False, True, False, (x := 2; True)], Print["Yes"], Print["No"]]; x
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12
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You can use And and still get what you want:

x := 1
If[And @@ {True, False, True, False, (x := 2; True)}, Print["Yes"], Print["No"]]; 
x

(* No
   2 *)

What happens is that the List and its arguments are evaluated before And is applied to it, hence setting the value of x.

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