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I have the following expression:

(1 - a) (H - 3 L*r + L)

and I would like to `simplify' this to

(1 - a) (H - L(3 r +1))

I thought that maybe Simplify or Collect could work, but to no avail.

What's the right function to achieve this?

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    $\begingroup$ expr = (1 - a) (H - 3 L*r + L); Collect[#, L] & /@ expr $\endgroup$ – Bob Hanlon Feb 2 at 21:34
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You can map HornerForm to each factor:

expr = (1 - a) (H - 3 L*r + L); 

HornerForm /@ expr
(1 - a) (H + L (1 - 3 r))
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