1
$\begingroup$

I want to find an instance of solution of a very complicated equation like

func[a, x, y, w, z] == c

that is a global minimum (within the solution set) of a.

Below is a minimum working example

Alfa = 1/137;
sw = Sqrt[0.23152];
mμ = 105.658*10^-3 (*GeV*);

Γμ = 1/(3.34*10^18);

gs = 1;
gU = 1/Sqrt[2] Sqrt[4  Pi Alfa]/sw;

BRfunction[MU_, Ms_, VU11_, VU12_, VU21_, O11_, O12_, O21_] := 
  (1/Γμ)*
    (mμ^5 (1/
       5 gs^4 MU^4 O11^2 (15 Ms^2 - 2 mμ^2) (O12^2 + O21^2) + 
       4 gs^2 gU^2 Ms^4 MU^2 O11 VU11 (O12 VU21 + O21 VU12) + 
       2 gU^4 Ms^6 VU11^2 (VU12^2 + VU21^2)))/(6144 π^3 Ms^6 MU^4);

FindInstance[
  BRfunction[MU, Ms, VU11, VU12, VU21, O11, O12, O21] == 10^(-12) && 
  MU > 100 && MU < 100000 && Ms > 100 && Ms < 100000 && O11 > -1 && 
  O11 < 1 && O12 > -1 && O12 < 1 && O21 > -1 && O21 < 1 && O11 != 0 &&
  VU11 > -1 && VU11 < 1 && VU11 != 0 && VU12 > -1 && VU12 < 1 && 
  VU21 > -1 && VU21 < 1 && VU21 <= Sqrt[1 - VU11^2] && 
  VU12 <= Sqrt[1 - VU11^2], 
  {MU, Ms, VU11, VU12, VU21, O11, O12, O21}]

But I don't want to find any instance, as the code would output, I want to find the instance that minimizes MU.

What is the most efficient way to do this?

Edit:

Following the first answer suggestion, I have done

FindInstance[
  BRfunction[MU, Ms, VU11, VU12, VU21, O11, O12, O21] == 10^(-12) && 
  MU > 100 && MU < 100000 && Ms > 100 && Ms < 100000 && O11 > -1 && 
  O11 < 1 && O12 > -1 && O12 < 1 && O21 > -1 && O21 < 1 && O11 != 0 &&
  VU11 > -1 && VU11 < 1 && VU11 != 0 && VU12 > -1 && VU12 < 1 && 
  VU21 > -1 && VU21 < 1 && VU21 <= Sqrt[1 - VU11^2] && 
  VU12 <= Sqrt[1 - VU11^2], 
  {MU, Ms, VU11, VU12, VU21, O11, O12, O21}]

but evaluating

  BRfunction[MU, Ms, VU11, VU12, VU21, O11, O12, O21]

using the set of variables given as solution by NMinimize with Method -> Automatic and PrecisionGoal -> 20 (and a little different constraints such as Abs[VU11]>0.1 which are definitely not relevant to the problem) I don't get the expected result of 10^(-12), but rather, at best, something to the order of 10^(-9).

$\endgroup$
5
  • $\begingroup$ Far too few details to even give you a suggestion. Can you make a simpler example (a Minimal Working Example, MWE) that represents what you are trying to do? $\endgroup$
    – MarcoB
    Jan 6, 2021 at 22:27
  • $\begingroup$ func[a_, x_, y_, w_, z_, c_] = a*x*y*w*z - c; NMinimize[{a, func[a, x, y, w, z, c] == 0}, {a, x, y, z, w, c}, Method -> Automatic] $\endgroup$
    – cvgmt
    Jan 6, 2021 at 22:52
  • $\begingroup$ @MarcoB I have added a MWE! $\endgroup$
    – GaloisFan
    Jan 6, 2021 at 22:58
  • 2
    $\begingroup$ Is there any reason not to use NMinimize or FindMinimum, specifying the "instance" qualifications as constraints? $\endgroup$ Jan 6, 2021 at 23:38
  • $\begingroup$ @Daniel Lichtblau Thanks for the suggestion! I have tried it, but then the required equation (enforced as a constraint) does not hold as expected. The issue is a little more detailed in the edited question. $\endgroup$
    – GaloisFan
    Jan 9, 2021 at 20:53

1 Answer 1

3
$\begingroup$

Maybe as below.

NMinimize[{MU, 
  BRfunction[MU, Ms, VU11, VU12, VU21, O11, O12, O21] == 10^(-12) && 
   MU > 100 && MU < 100000 && Ms > 100 && Ms < 100000 && O11 > -1 && 
   O11 < 1 && O12 > -1 && O12 < 1 && O21 > -1 && O21 < 1 && O11 != 0 &&
    VU11 > -1 && VU11 < 1 && VU11 != 0 && VU12 > -1 && VU12 < 1 && 
   VU21 > -1 && VU21 < 1 && VU21 <= Sqrt[1 - VU11^2] && 
   VU12 <= Sqrt[1 - VU11^2]}, {MU, Ms, VU11, VU12, VU21, O11, O12, 
  O21}]
$\endgroup$
3
  • $\begingroup$ I had to unaccept your answer by the reason added to the question. I upliked it for now! $\endgroup$
    – GaloisFan
    Jan 9, 2021 at 4:09
  • 1
    $\begingroup$ To @GaloisFan and @cvgmt Do your NMinimize with eqs// Rationalize[#, 0] & and , WorkingPrecision -> 40, MaxIterations -> 1000 to get BRfunction[MU, Ms, VU11, VU12, VU21, O11, O12, O21] /. %[[2]] (* 1.*10^-12 *) $\endgroup$
    – Akku14
    Jan 10, 2021 at 7:17
  • $\begingroup$ sol = NMinimize[{MU, (BRfunction[MU, Ms, VU11, VU12, VU21, O11, O12, O21] == 10^(-12) // Rationalize[#, 0] &) && MU > 100 && MU < 100000 && Ms > 100 && Ms < 100000 && O11 > -1 && O11 < 1 && O12 > -1 && O12 < 1 && O21 > -1 && O21 < 1 && O11 != 0 && VU11 > -1 && VU11 < 1 && VU11 != 0 && VU12 > -1 && VU12 < 1 && VU21 > -1 && VU21 < 1 && VU21 <= Sqrt[1 - VU11^2] && VU12 <= Sqrt[1 - VU11^2]}, {MU, Ms, VU11, VU12, VU21, O11, O12, O21}, WorkingPrecision -> 40, MaxIterations -> 1000] BRfunction[MU, Ms, VU11, VU12, VU21, O11, O12, O21] /. sol[[2]] $\endgroup$
    – cvgmt
    Jan 10, 2021 at 8:07

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.