I have a phrase that in it x is a function of y but I need to plot y as a function of x. I tried InverseFunction but because my phrase is not single-valued in some points Mathematica can not give me a plot. After that, I tried ParametricPlot
but this code has not any answer. In fact I wanna inverse x
and y
axes. what should I do?
0.008 y +
125. (2. -
0.0000271476 (659.714/(1 - 0.169673 y) + (
2 (2.30388*10^-6 + 0.169673 y)^2)/(1 - 0.169673 y)^2) - (
0.00271476 (2.30388*10^-6 + 0.169673 y))/(1 - 0.169673 y))^2 y=x
Plot[{0.008 y +
125. (2. -
0.0000271476 (659.714/(1 - 0.169673 y) + (
2 (2.30388*10^-6 + 0.169673 y)^2)/(1 - 0.169673 y)^2) - (
0.00271476 (2.30388*10^-6 + 0.169673 y))/(1 - 0.169673 y))^2 y}, {y, 5.6, 6}]
Plot[2.3864*10^-15 y + 9.5456*10^-15 (25. - 2.78813*10^-9 (659.714/(1 - 5.57627*10^-9 y) + ( 2 (9.21551*10^-6 + 1.39407*10^-6 y)^2)/(1 - 5.57627*10^-9 y)^2) - ( 1.39407*10^-6 (9.21551*10^-6 + 1.39407*10^-6 y))/( 1 - 5.57627*10^-9 y))^2 y, {y, 1.7*10^8, 1.9*10^8}]
when I plotted these function no minus region appear but when I plotted inverse function with ParametricPlot some region that are minus in sign will appear, why is that? $\endgroup$