I am trying to visualize a 3D section of a chopped up 1x1x1 Cube. I don't want to use the Cube function to draw this. (unless you think you can still accomplish it that way). Ok, so say you have a simple XY plane, laying flat on the table (lengths 1x1) Now I draw 2 straight lines across it with equations: Y=X+1/2 and Y=X-1/2 and shade the region in between. (it'll take up 75% of the 1x1 region of course with the top left and bottom right squares being half shaded now, and the other 2 squares fully shaded). Ok simple enough so far.
Now let's draw up the Z-axis above this (Hold the ruler perpendicular to the table up to a height of 1). Now raise/stretch that same shaded region above to the top, which will still take up the 75% of the now-8 0.5x0.5 cubes). with 2/8 unshaded. Ok now imagine the ZX plane (facing you on the table) and draw up the same 2 equations, now: Z=X+1/2 and Z=X-1/2 so you now have the same regions covering the ZX plane and they now travel to the back of the Cube - and the main point, now intersect the previous region (coming up from XY plane).
I like to visualize both shaded intersection. In other words, how can I draw up both regions, shade them, then put them into 3D for both planes and be able to rotate that final 3D image in any direction I like to visualize that highlighted 3D-intersection.
P.S. Too much in language, for those who like pure equations, in a nutshell this is all I need:
Y=X(+/-)1/2 and Z=X(+/-)1/2 < == 3D Plot and visualize intersection region in between the 2 pairs of lines on each plane.
Assume/hope your solution can take in any Function cutting the cube: Say Y=f(X) and Z=g(X)?
Co-incidentally, assume this is also possible to solve algebraically?