Riemann's prime counting function J (link) takes half-values at every jump-discontinuity. So, I define it thus:

floor[e_] := Quiet[Check[Floor[e], Floor[FullSimplify[e]]]]; 
riemannJ[x_] :=
   With[{δ = 0.01}, 
       {(Sum[(1/α)* PrimePi[(x - δ)^(1/α)],
        {α, 1, floor[Log[x - δ]/Log[2]]}] + Sum[(1/α)*
        PrimePi[(x + δ)^(1/α)], {α, 1, 
        floor[Log[x + δ]/Log[2]]}])/2,
       {Sum[(1/α)*PrimePi[x^(1/α)], {α, 1, 

Viewed as a Plot, the function J[x]*x^(-s - 1) produces a series of continuous lines that are discontinuous from each other at all points where PrimePowerQ[x] = True (plot shown with with s = -2):

Module[{s = -2}, 
 Plot[riemannJ[x]*x^(-s - 1), {x, 1, 10}, GridLines -> Automatic]

plot with error: primepower argument is not exact number

I have a couple of problems:

  1. That error message: is Mathematica passing inaccurate values of x to Plot?

  2. I'd like to use Manipulate to chart the curve for different values of s. But the plot now has a pink fill. The code is:

     Plot[riemannJ[x]*x^(-s - 1), {x, 1, 10}, GridLines -> Automatic], 
     {{s, -2, Style["Choose s", Larger, Bold]}, -5, 5, 1/2}, 
     ControlType -> Setter]

and the output:

output of manipulate with same error and plot with pink background

I assume that this is the same error (as evidenced but the line below the plot), only now it shows the plot in pink.

How do I get around this?


  1. Is there a way to 'join up' the line segments at the points of discontinuity?
  • 1
    $\begingroup$ “ is Mathematica passing inaccurate values of x to Plot?” - Plot is passing machine-precision values to your function as it evaluates it in the plotting range you chose. Those values are passed to PrimePowerQ, which complains because its input should be arbitrary-precision. You should sanitize your inputs to riemannJ. $\endgroup$ – MarcoB Nov 16 at 14:35
  • $\begingroup$ Hi @MarcoB. OK - but I have no idea how to do that... $\endgroup$ – Richard Burke-Ward Nov 16 at 14:38
  • $\begingroup$ oops, sorry @MarcoB - saw your comment after I posted.. Same answer $\endgroup$ – George Varnavides Nov 16 at 14:41
  • $\begingroup$ @GeorgeVarnavides Not a problem! I am glad you put together a proper answer instead. $\endgroup$ – MarcoB Nov 16 at 17:44

PrimePowerQ only takes exact numbers as arguments.

In[1]:= PrimePowerQ[1.2]
During evaluation of In[1]:= PrimePowerQ::exact: Argument 1.2` in PrimePowerQ is not an exact number.
Out[1]= PrimePowerQ[1.2]

Plot is happy to ignore the unevaluated Piecewise calls (which is why you also get the discontinuities).

All three questions are fixed by replacing PrimePowerQ[x] with PrimePowerQ[Rationalize[x,0]].

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