I wanted to expand the function $(x+2)^{x+2}$ around $x = -1$, that is, using
Series[(x + 2)^(x + 2), {x, -1, 2}]
and Mathematica returns the same expression. Why does this happen? The first term of a series expansion is simply $1^1 = 1$. However, I cannot even get this, from
Series[(x + 2)^(x + 2), {x, -1, 0}]
Series[(x + 2)^(x + 2), {x, x0, 2}] /. x0 -> -1
works. $\endgroup$Series[(x + 2)^(x + 2), {x, -1, 2}]
gives1 + (x+1) + (x+1)^2 + O[x+1]^3
. AndSeries[(x + 2)^(x + 2), {x, -1, 0}]
gives1 + O[x+1]^1
. Do you use a fresh kernel? $\endgroup$Series[(x + 3)^(x + 3), {x, -2, 2}]
gives1+(x+2)+(x+2)^2+O[x+2]^3
. (v9.0.1) $\endgroup$Series[(x + 2)^(x + 2), {x, -1, 2}]
gives1 + (x+1) + (x+1)^2 + O[x+1]^3
with v8.0.1 but(2 + x)^(2 + x)
with v9.0.0. Seems to be a bug in the new version. This brings me to two questions: 1. Where to report such a bug? 2. Does Wolfram provide updates so that one can work with a software which has less bugs? $\endgroup$