How to have DiscretePlot of a domain with different criteria for different subdomains?

Question

If I have three criteria for the domain of $m\in\{1,2,3,4,5,6,...,22\}$ as

$$f(m)= \cos \left(\frac{\pi ^5 m}{4}\right)\quad for \quad m=3,6,12,15,21$$ $$g(m)=\frac{1}{\sin \left(\frac{\pi m}{3}\right)}\quad for \quad m=1,2,4,5,7,8,10,11,13,14,16,17,19,20,22$$ $$h(m)=10\quad for \quad m=9,18$$

then how can I have one DiscretePlot for all $m\in\{1,2,3,4,5,6,...,22\}$, and then join the adjacent numbers.

f[m_] = Cos[(m (\[Pi]^5) )/4] for m = 3, 6, 12, 15, 21

g[m_] = Sin[(m \[Pi] )/3]^-1   for    m = 
  1, 2, 4, 5, 7, 8, 10, 11, 13, 14, 16, 17, 19, 20, 22

h[m_] = 10 for m = 9, 18

Answer 1

{domf, domg, domh} = {{3, 6, 12, 15, 21}, {1, 2, 4, 5, 7, 8, 10, 11, 13, 14, 16,
     17, 19, 20, 22}, {9, 18}};

pw[m_] := Piecewise[{{Cos[(m (π^5))/4], MemberQ[m]@domf},
     {Sin[(m π)/3]^-1, MemberQ[m]@domg},
     {10, MemberQ[m]@domh}}]

DiscretePlot[pw[m], {m, Range[22]}, PlotRange -> All]

Alternatively,

fgh[m : Alternatives @@ domf] := Cos[(m (π^5))/4]
fgh[m : Alternatives @@ domg] := Sin[(m π)/3]^-1
fgh[m : Alternatives @@ domh] := 10

DiscretePlot[fgh[m], {m, Range[22]}, PlotRange -> All]

same picture

Answer 2

list1 = {3, 6, 12, 15, 21};
list2 = {1, 2, 4, 5, 7, 8, 10, 11, 13, 14, 16, 17, 19, 20, 22};
list3 = {9, 18};
list = Union[list1, list2, list3];
f[m_ /; MemberQ[list1, m]] = Cos[(π^5 m)/4];
g[m_ /; MemberQ[list2, m]] = 1/Sin[(π m)/3];
h[m_ /; MemberQ[list3, m]] = 10;
DiscretePlot[{f[m], g[m], h[m]}, {m, list}, 
 PlotStyle -> {Red, Green, Blue}, PlotRange -> All]