# plotting parabolas

I had to redo the problem because there was a mistake. With the given function from a previous problem, I was solving link, I found that the parabola created a trajectory on the graph, ie another parabola.

I'm trying to create a plot where I collect the coordinate points of Min. value for 21 values of parameter a (from -7 to 7), and find a,b, and c such that the points are on the curve of the quadratic equation $$ax^2+bx+c=y$$. The plot looks something like this The curve of $$ax^2 + b+x +c=y$$ goes through all the minimum points for the curves created

I am not sure if I understood the question correctly. Does this solve your question?

Table[{Plot[x^2-2*(a-2)*x+a-2,{x,-20,20}],{a-2,-6+5 a-a^2}},{a,Range[-7,7,14/20]}];
Show[Flatten[{%[[All,1]],Plot[x-x^2,{x,-20,20},PlotStyle->Red],ListPlot[%[[All,2]]]}]]
-6+5 a-a^2/.a->x+2//Expand I used the code from https://mathematica.stackexchange.com/a/231665/42436 to generate the parabolas and from the formula for the minima {a-2,-6+5 a-a^2} one can directly compute the parabola on which all minima are found: $$x-x^2=y\\ a x^2+b x+c=y\quad\text{with}\quad \{a=-1,b=1,c=0\}$$

• How can I find the coordinates using Solve command? – computer891 Oct 19 '20 at 21:15
• What coordinates? – N0va Oct 19 '20 at 21:18
• nevermind, it was found using table command. – computer891 Oct 19 '20 at 21:58

To get the trajectory equation about the minimum, we can do as below.

f[x_, a_] := x^2 - 2*(a - 2)*x + a - 2;
min = Minimize[f[x, a], x];
Eliminate[{x, y} == ({x, y} /. Last@min /. y -> First@min), a]


-y == -x + x^2

To plot the minimum points, here we also use Mesh.

Clear["*"];
f[x_, a_] := x^2 - 2*(a - 2)*x + a - 2;
curves = Plot[Table[f[x, a], {a, -7, 7, 14/20}], {x, -20, 20},
PlotStyle -> {Thickness[Small], Cyan}];
min = Minimize[f[x, a], x];
trajectory =
ParametricPlot[{x, y} /. Last@min /. y -> First@min, {a, -9, 9},
MeshFunctions -> Function[{x, y, a}, a],
Mesh -> {Range[-7, 7, 14/20]},
MeshStyle -> {PointSize[Medium], Red}, PlotStyle -> Yellow];
Show[curves, trajectory]


Another way is Show the minimum points by Graphics

points = Graphics[{Red,
Table[Point[{x, y} /. Last@min /. y -> First@min], {a, -7, 7,
14/20}]}];
` 