# Strange result from evaluating a Limit expression

Bug introduced in 9.0 and fixed in 10.0

When I evaluate the limit of (1-Cos[x]) Sin[1/x] at x = 0 in Mathematica 9, I obtained Interval[{-2, 2}]. The problem is that this limit is 0. It is also 0 when I compute it by Maple and Mathematica 7. So, I wonder whether I've found a bug in Mathematica 9?

Limit[(1 - Cos[x]) Sin[1/x], x -> 0]
Interval[{2, 2}]
• Are you sure that you didn't write by mistake (1+Cos[x]) Sin[1/x]? Apr 11, 2013 at 1:45
• What subversion of 9 you have? Did you run the command after a initializing the kernel? If this is true its a big mess up! It's like saying that $\cos(0)=-1$! Apr 11, 2013 at 2:04