I am trying to follow my teacher's instructions to easily compute for a complex conjugate but I get mathematica to actually reveal the complex conjugate besides the word "conjugate" and even with that the outputs don't seem to match my professor's for Quantum mechanics class. I'm not sure if the coding my professor used is no longer valid, but I really would like to get a handle on this for much more complex (no pun intended) functions involving imaginary numbers and such. I appreciate any assistance in this regard.

This a picture I PrtSc for a better look at what I did

My own input and attempt to compute for a complex conjugate

And Here's what my professor was able to do but I can't emulate despite multiple attempts What it's supposed to look like according to my professor I.

Page 2 of what it's supposed to look like according to my professor

  • 1
    $\begingroup$ Use a + I b instead of a + Ib $\endgroup$ – Carl Woll Sep 20 '20 at 0:28
  • $\begingroup$ Thanks so much Carl, that seemed to do it! You have saved me from pulling my hair out. $\endgroup$ – Biometric09 Sep 20 '20 at 0:32
  • $\begingroup$ Well ok, it worked until I got to Input 6 $\endgroup$ – Biometric09 Sep 20 '20 at 0:38

ComplexExpand is powerful.

f[x_] := E^(-(a + I*b) x);
f[x] // ComplexExpand
Conjugate[f[x]] // ComplexExpand
  • $\begingroup$ Thankyou very much $\endgroup$ – Biometric09 Sep 20 '20 at 0:52
  • $\begingroup$ @Biometric09 Yes, you can attach your code in the question. $\endgroup$ – cvgmt Sep 20 '20 at 0:54
  • $\begingroup$ Can you do that for a comment, such as the one I'm doing now, or would I have to post a new question. Further, if I do post a new question, how do I post the code that I am attempting to do? $\endgroup$ – Biometric09 Sep 20 '20 at 1:01
  • $\begingroup$ @Biometric09 you can edit your question if you wish. Just click the pencil icon. You follow markdown formatting rules, which there should be links to the details of when you are formatting the edit to your question. $\endgroup$ – CA Trevillian Sep 20 '20 at 4:54

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.