4
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I tried the following code

ContourPlot3D[x^2 + y^2 + z^2 == 1, {x, y, z} \[Element] Cube[2], RegionBoundaryStyle -> None]

And I got only this opaque cube. So I cannot see the contour surface I am trying to plot. How can I fix this?

enter image description here

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3
  • $\begingroup$ The Element region is a new feature,maybe a bug. ContourPlot3D[ x^2 + y^2 + z^2 == 1, {x, -1, 1}, {y, -1, 1}, {z, -1, 1}, RegionFunction -> Function[{x, y, z, f}, f = True], RegionBoundaryStyle -> Automatic] $\endgroup$
    – cvgmt
    Aug 26 '20 at 11:52
  • $\begingroup$ @cvgmt Thanks. But I am trying to make {x, -1, 1}, {y, -1, 1}, {z, -1, 1} a little bit shorter. $\endgroup$
    – ablmf
    Aug 26 '20 at 12:01
  • 2
    $\begingroup$ Please report this to Support. $\endgroup$
    – J. M.'s torpor
    Aug 26 '20 at 16:41
3
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It is a bug! We can compare with the follwing two result.

       GraphicsGrid[{{ContourPlot3D[
    x y z, {x, y, z} ∈ 
     ImplicitRegion[x + y <= 1 , {x, y, z}], 
    RegionBoundaryStyle -> Opacity[0.1], ContourStyle -> Green, 
    Mesh -> False, PlotPoints -> 50],
   ContourPlot3D[
    x y z, {x, y, z} ∈ 
     ImplicitRegion[-1 <= x <= 1 , {x, y, z}], 
    RegionBoundaryStyle -> Opacity[0.1], ContourStyle -> Green, 
    Mesh -> False, PlotPoints -> 50]}}]

enter image description here

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1
  • $\begingroup$ So, to be clear, you were able to workaround the bug by using GraphicsGrid? Have you found any other methods? $\endgroup$ Aug 30 '20 at 3:46

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