4
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I would like to know how I can divide the attached list of points to as many clusters as possible based on the gap between the patches. Then I can decide which one should be kept and which remove. I tried different options in Findclusters command but none of them gave me a correct answer. Any help is really appreciated.

https://pastebin.com/WMC4GhxE

enter image description here

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This gets you four clusters with points grouped together in ccmp. The two large islands are depicted in orange and blue, the small long island in green, and a tiny island in red.

nng = NearestNeighborGraph[data, 8];
ccmp = ConnectedComponents[nng];
ListPointPlot3D[ccmp]

(* Length@ccmp == 4 *)

connected components list plot

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  • $\begingroup$ Thank you! It worked! However, when I changed the value of the coefficient in the bracket of the NeasrestNeighborGraph from 8 to 4, the number of patches changed to 5 and showed me another small island as a separate cluster which is correct basically. Is there any criterion to select the value of the coefficient? For example, the value of 1 gave me 30 patches. I am asking as I need to apply the script on different data and need to use a constant coefficient. $\endgroup$ – Mehdi Ebadi Jun 13 '20 at 17:27
  • $\begingroup$ I just chose 8 randomly. If instead you put a list {k,r} it uses the k nearest within distance r, and {All,r} connects all elements within distance r $\endgroup$ – flinty Jun 13 '20 at 17:31
  • $\begingroup$ Thank you for the response! By distance, you mean Euclideandistance? $\endgroup$ – Mehdi Ebadi Jun 13 '20 at 17:38
  • $\begingroup$ Yes by default, but it also takes an option DistanceFunction, e.g , DistanceFunction -> ManhattanDistance $\endgroup$ – flinty Jun 13 '20 at 17:43
  • $\begingroup$ Another question and appreciate your response. Is always the output from the largest list (with the most number of members) to the smallest one? $\endgroup$ – Mehdi Ebadi Jun 13 '20 at 18:29

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