I want to produce {Foo[a,b, c], Goo[a, b, c], Hoo[a, b, c]}. However my attempt below

Thread[Apply[{Foo, Goo, Hoo}, HoldComplete@Sequence[a, b, c]]]

produces {Foo, Goo, Hoo}[a, b, c].

Could you fix it?

  • $\begingroup$ Construct[#, Sequence[a,b,c]] & /@ {Foo, Goo, Hoo} ... or if you want to keep the hold and release: ReleaseHold[Construct[#, HoldComplete@Sequence[x, y, z]] & /@ {Foo, Goo, Hoo}] $\endgroup$ – flinty Jun 11 at 0:45
  • $\begingroup$ Let me know if my solution would work for you, or how I might improve it :D $\endgroup$ – CA Trevillian Jun 11 at 0:55
  • $\begingroup$ @flinty: Thank you. $\endgroup$ – user69652 Jun 11 at 3:00

Consider Through:

Through[{Foo, Goo, Hoo} @@ {a, b, c}]
{Foo[a, b, c], Goo[a, b, c], Hoo[a, b, c]}

Alternatively, use it as:

Through @ {Foo, Goo, Hoo}[a, b, c]
{Foo[a, b, c], Goo[a, b, c], Hoo[a, b, c]}

Or make it into a function:

boohoo = Through[# @@ #2] &;

{Foo, Goo, Hoo} ~ boohoo ~ {a, b, c}
 {Foo[a, b, c], Goo[a, b, c], Hoo[a, b, c]}
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Let me know if you need an explanation. I figure a list of both functions and arguments would be the simplest method. Then I just made sure the Map over the functions would cause them to Apply to the arguments.

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  • 1
    $\begingroup$ @MoneyOrientedProgrammer glad to hear it! Looks like kglr beat me again though haha D; $\endgroup$ – CA Trevillian Jun 11 at 3:47

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