3
$\begingroup$

I have a complicated fraction

1/(4 TauTheta)+TauU/(gamma^2 (1+J)^2 TauDelta (1/TauEpsilon+1/(4 TauTheta)+(-1+J)/(4 TauTheta))^2 (TauDelta+TauU/(gamma^2 (1/TauEpsilon+1/(4 TauTheta)+(-1+J)/(4 TauTheta))^2)))-((1+J)^2 TauTheta+4 z1)/(4 (1+J)^2 TauTheta (TauTheta+z1))-TauU/(gamma^2 (1+J)^2 TauDelta (1/TauEpsilon+(-1+J)/(4 TauTheta)+1/(4 (TauTheta+z1)))^2 (TauDelta+TauU/(gamma^2 (1/TauEpsilon+(-1+J)/(4 TauTheta)+1/(4 (TauTheta+z1)))^2)))

Here is what it looks like. enter image description here

I want to simplify it into a factor with one layer, which means it looks like a/b. However, whenever I use Simplify or FullSimplify, it does not change.

enter image description here

Could anyone help me? Thanks in advance!

$\endgroup$
4
$\begingroup$

Together seems to do the trick:

FullSimplify@Together@Test
(* (z1 (256 (-1 + J) (3 + 
        J) TauEpsilon^4 TauTheta^4 TauU^2 (TauTheta + z1)^2 + 
     16 gamma^2 TauEpsilon^2 TauTheta^2 TauU (2 TauTheta^2 (J 
TauEpsilon + 4 TauTheta) ((-1 + J) J (3 + J) TauDelta TauEpsilon + 
           4 (-1 + J) (3 + J) TauDelta TauTheta - 
           4 TauEpsilon TauTheta) + 2 TauTheta ((-1 + J) J (3 + J) (-1 + 
              2 J) TauDelta TauEpsilon^2 + 2 (-1 + 4 J) (2 (-1 + J) (3 + J) TauDelta - 
              TauEpsilon) TauEpsilon TauTheta + 32 ((-1 + J) (3 + J) TauDelta - TauEpsilon) TauTheta^2) z1 + (4 TauEpsilon (TauEpsilon 
- 2 J TauEpsilon - 8 TauTheta) TauTheta + (-1 + J) (3 + 
              J) TauDelta ((1 + 2 (-1 + J) J) TauEpsilon^2 + 
              8 (-1 + 2 J) TauEpsilon TauTheta + 32 TauTheta^2)) z1^2) + 
     gamma^4 (-1 + J) (3 + J) TauDelta^2 (J TauEpsilon + 
        4 TauTheta)^2 (-TauEpsilon z1 + J TauEpsilon (TauTheta + z1) + 
        4 TauTheta (TauTheta + z1))^2))/(4 (1 + 
     J)^2 TauTheta (gamma^2 TauDelta (J TauEpsilon + 4 TauTheta)^2 + 
     16 TauEpsilon^2 TauTheta^2 TauU) (TauTheta + 
     z1) (16 TauEpsilon^2 TauTheta^2 TauU (TauTheta + z1)^2 + 
     gamma^2 TauDelta (-TauEpsilon z1 + J TauEpsilon (TauTheta + z1) + 4 TauTheta (TauTheta + z1))^2)) *)

You can find this and many other function in the "Formula Manipulation" guide page.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.