Here is my code.

t0 = 1
t1 = 1

dvector[kx_, ky_, m_] := {t1*Sin[kx], t1*Sin[ky], t0*(Cos[kx] + Cos[ky] - m)}

dcap[kx_, ky_, m_] := 
 dvector[kx, ky, m]/Sqrt[Dot[dvector[kx, ky, m], dvector[kx, ky, m]]]

f[kx_, ky_, m_] := 
 Dot[dcap[kx, ky, m], (D[dcap[kx, ky, m], kx]\[Cross]D[dcap[kx, ky, m], ky])]

g[m_] := (NIntegrate[
     f[kx, ky, m], {kx, 0, 2*π}, {ky, 0, 2*π}]/(4*π)) // Chop


(**-- Next one is Very slow --**)


Whenever the absolute value of the argument in $g$ is greater than 2, it takes too long to evaluate the answer (which is zero), and it also shows errors in the numerical integration.

How to fix this? I want to plot $g$ as a function of its argument, which is taking way too much time due to the slowness to evaluate $g$ when $|m|>2$.


1 Answer 1

  • To solve the problem of calculating the value of an integral that is actually $0$, you can set a lower AccuracyGoal, as Andrew Moylan mentioned in this previous question here: "When the true value of the integral is zero, the default PrecisionGoal can never be satisfied. You need to set a finite AccuracyGoal in such cases".

  • To increase the integration speed, it is always a good idea to try different integration methods. In your case, the "GaussKronrod" method seems to works much faster.

With those changes:

g[m_] := Chop[
     f[kx, ky, m], {kx, 0, 2*π}, {ky, 0, 2*π},
     Method -> "GaussKronrodRule", AccuracyGoal -> 8

g[3] // AbsoluteTiming

(* Out: {0.0853762, 0} *)

You can then plot your integral in a reasonable time:

Plot[g[m], {m, -4, 4}, PlotPoints -> 20, MaxRecursion -> 5]

plot of integral value

  • $\begingroup$ Why did you choose GaussKronrod? Does it usually work faster for oscillatory functions? $\endgroup$ Commented Jun 1, 2020 at 3:59
  • $\begingroup$ And what does MaxRecursion do here? $\endgroup$ Commented Jun 1, 2020 at 4:29
  • $\begingroup$ 1. I tried a few methods and that one seemed fastest, certainly faster than the automatically selected one, 2) MaxRecursion limits the number of further subdivisions among plot points. I find that I typically want to control that as well when I increase the number of plot points, to make sure the plot doesn’t take too long, it’s a guessing game: quality and speed are always in a compromise, so I try a few values until I get good enough quality and fast enough execution. $\endgroup$
    – MarcoB
    Commented Jun 1, 2020 at 4:50

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