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I had an equation in which I replaced two of my variables k and n with their logarithmic counterpart variables logk and logn as follows :

eq = (Binomial[n, 2]*(3.97887*10^-10 Cos[200 k ArcSinh[50/k]])/
       Sqrt[1 + 2500/k^2] == -0.00003 // Rationalize) /. {n -> 
    10^logn, k -> 10^(-logk)}

Then I solved for one of the variables logn :

solk[logn_] := 
 logk /. NSolve[{(1.9894350000000002`*^-10 10^logn (-1 + 10^logn) Cos[
          200 (10^-logk)* ArcSinh[5*10^2 (10^logk)]])/
       Sqrt[1 + (25*10^2 10^(2 logk))] == -(3/10000), -65 < logk < 0},
     logk, Reals][[1]]

And finally plotted :

p1 = Plot[2.0*solk[logn], {logn, 0, 23}, 
  PlotRange ->All]

The plot I get has the y-axes and x-axes values as the powers of 10 (since my base of log is 10).

I just want to convert to the normal values i.e. for example instead of showing 0,1,2,..,23 on x-axis I would like to show 10^1, 10^2,..., 10^23 How can I do this?

The answer could be in either of two formats :-

i) Truly converting the x and y values to decimal scale and showing as such on the plot

ii) Merely a relabelling of the values shown on the axis.

It seems trivial but I can't figure it out!

Note : A small caveat is to note that I have values which range upto 10^23 in the calculation and I can't just use k and n instead of logk and logn because of some reason.

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  • $\begingroup$ Ummm... what is logn? What is logk? $\endgroup$ Apr 25, 2020 at 23:36
  • $\begingroup$ @DavidG.Stork It is mentioned in the first codeblock. Basically n = 10^logn and k=10^-logk. They are just scaled variables related to n and k $\endgroup$
    – Nitin
    Apr 25, 2020 at 23:53

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