Simplify without changing the denominator

Question

I have the following expression:

    1/2 (-c y - 2/((2 + x) (1 - δ)) + (
    2 (1 + y))/((2 + x + y) (1 - δ))) + 
1/4 (-c x - c y + 
    1/4 (1/(1 - δ) - (2 (1 + x))/((2 + x) (1 - δ))) + 
    1/4 (1/2 (c x + 1/(1 - δ) - (
          2 (1 + x))/((2 + x) (1 - δ))) + 
       1/2 (c y + 1/(1 - δ) - (
          2 (1 + y))/((2 + y) (1 - δ))) - 2/(1 - δ) - 
       2/((2 + x) (1 - δ)) - 2/((2 + y) (1 - δ))) + 
    1/4 (1/2 (-c x - 1/(1 - δ) + (
          2 (1 + x))/((2 + x) (1 - δ))) + 
       1/2 (-c y - 1/(1 - δ) + (
          2 (1 + y))/((2 + y) (1 - δ))) + 2/(1 - δ) + 
       2/((2 + x) (1 - δ)) + 2/((2 + y) (1 - δ))) + (
    2 (1 + x))/((2 + x + y) (1 - δ)) + (
    2 (1 + y))/((2 + x + y) (1 - δ)))

I want to simplify without changing the denominator. For example, you see that the terms:

-c y; -c x

appears many times. Also the term:

/((2 + x + y)

Also appear many times. I want to simplify those, by taking out. For example:

1/2 (-c y - 2/((2 + x) (1 - δ)) + 1/4 (-c x - c y)

when simplify, my desired result would have:

-3/4 c y

How to do that? If I just use simplify for the entire thing, the result will be:

-((8 (4 + y (4 + 6 c (-1 + δ)) + 3 c y^2 (-1 + δ)) + 
  x^2 (7 + 16 c (1 + y) (-1 + δ)) + 
  x (30 + 23 y + 4 c (4 + 14 y + 3 y^2) (-1 + δ)) + 
  4 c x^3 (-1 + δ))/(16 (2 + x) (2 + x + y) (-1 + δ)))

Which I do not want.

Answer 1

I used Expand and got what I needed