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I want the simplest way of exporting matrices, and vector from mathematica to Latex.

Usually, I display my matrices in MatrixForm and copy as Latex to paste in my latex document. However it seems it doesn't always work, take the following code:

vv = {1, 2};
vv // MatrixForm

If from the display you do "copy as -> Latex", it returns you:

\{1,2\}

Instead of (for example):

\begin{pmatrix} 1 \\ 2 \end{pmatrix}

Which would match the mathematica display. If I input a matrix however (thus having more than 1 column), it works as it should.

How to make it really returns me something that will look like a column vector in latex ?

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  • $\begingroup$ In version 12, I only get array, not pmatrix. $\endgroup$
    – Henrik Schumacher
    Jan 16, 2020 at 13:10
  • $\begingroup$ @HenrikSchumacher I don't necesserally want a pmatrix and indeed it is not what it returns me for a "real" matrix (not a column vector). But I want a proper array to represent the column vector which he doesn't give me. $\endgroup$
    – StarBucK
    Jan 16, 2020 at 13:45

1 Answer 1

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What about

export[v_?VectorQ] := export@Partition[vv, 1];
export[A_?MatrixQ] := CopyToClipboard@TeXForm@A;

and then

vv // export

?

A way to enforce pmatrix could be

export[v_?VectorQ] := export@Partition[vv, 1];
export[A_?MatrixQ] := CopyToClipboard@StringJoin[
    "\\begin{pmatrix}\n",
    ExportString[
     Join[
      Map[TeXForm, A, {2}],
      Append[ConstantArray["\\\\", {Length[A] - 1, 1}], {""}],
      2],
     "Table",
     "FieldSeparators" -> " & "
     ],
    "\n\\end{pmatrix}"
    ];

Btw., MatrixForm is super superfluous here.

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  • $\begingroup$ Thank you for your answer. So actually the "real" answer inside is that I have to do Partition[vv, 1] to tell mathematica to write it as a matrix (even if it is a column vector). So that when I export in latex he knows he has to write a column vector using array. Would you confirm ? $\endgroup$
    – StarBucK
    Jan 16, 2020 at 13:47
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    $\begingroup$ Mathematica just does not distinguish between "column vectors" and "row vectors". But you can transform an $n$-vector v into a $n \times 1$-matrix with Partition[v,1]. Btw., I strongly believe that Mathematica is a "she". But who knows...? $\endgroup$
    – Henrik Schumacher
    Jan 16, 2020 at 13:52
  • $\begingroup$ Ok thanks. Well actually I'm french so I sometime replace it by he or she as we don't have impersonal pronouns ^^ $\endgroup$
    – StarBucK
    Jan 16, 2020 at 14:00

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