How to solve a matrix PDE and stop solving when solution becomes singular?

Question

My question consists of two parts:

1. How do I get mathematica to solve a PDE Matrix system and plot the result? See below for the PDE matrix system. (By plot the result I mean plot the region where the solution $\Theta$ is nonsingular.)
2. How do I stop the integration when the solution matrix becomes singular? I know that away from $(x_1,x_2)=(0,0)$ the solution matrix $\Theta$ will become singular how do I stop Mathematica from trying to solve pass this point?

The PDE matrix system I am trying to solve is \begin{align} \lambda \Theta(x_1,x_2)&=\dot{\Theta}(x_1,x_2)+\Theta(x_1,x_2)A &\quad \text{Equation}\\ \Theta(0,0)&=\begin{pmatrix} 1 & -\frac{1}{2} -\frac{\sqrt{3}}{2} \\ 1 & -\frac{1}{2}-\frac{1}{2\sqrt{3}}+\frac{2}{\sqrt{3}} \end{pmatrix} &\quad \text{Initial condition} \end{align} I have specified the values of $\dot{\Theta}(x_1,x_2),A,\lambda$ in the block below:

(* Definitions *)
A = {{-(x1^2 - 1), -2 x2 x1 - 1}, {1, 0}}
lambda = {{1/2, -Sqrt[3]/2}, {Sqrt[3]/2, 1/2}}
(*Value of theta for x1=x2=0 *)
ThetaInit = {{1, -1/2 - Sqrt[3]/2}, {1, -1/2 - 1/(2 Sqrt[3]) + 
    2/Sqrt[3]}}
(*Derative of Theta in terms of t. Note \
\frac{dtheta}{dt}=x1'(t)\frac{\partial theta}{\partial x1}+x2'(t) \
\frac{\partial theta}{\partial x2} *)
ThetaDot = ( -(x1^2 - 1) x2 - x1) D[Theta[x1, x2], x1] + 
  x2 D[Theta[x1, x2], x2]

Note the initial condition is satisfied as

lambda.ThetaInit == ThetaDot + ThetaInit.A /. {x1 -> 0, x2 -> 0}

yields true.

Notes

• If you need any clarification please feel free to ask.
• This problem comes from https://dspace.mit.edu/bitstream/handle/1721.1/9793/42916380-MIT.pdf?sequence=2 I am trying to reproduce the simulation in Mathematica see pages 64-66. I did not share this before because the details are fairly confusing.
• There was an error in the PDE I corrected that error.
• Because people where confused $$\dot{\Theta}(x_1,x_2)=( -(x_1^2 - 1) x_2 - x_1) \frac{\partial \Theta}{\partial x_1}+ x_2 \frac{\partial \Theta}{\partial x_2}$$