I would like to add constraints on a model and its derivatives and then use FindFit to fit some parameters. An example is below:

modelt[a_?NumberQ, k_?NumberQ] := (modelt[a, k] = 
First[x /.NDSolve[{x'[t] == (1/2)*y[t]*(Sin[x[t] + a] + Cos[x[t] + a]), 
y'[t] == k Sin[x[t]], x[0] == Pi/2, y[0] == 1/2}, {x,  y}, {t, 0, 1000}]])

FindFit[{1000, Pi/6}, {modelt[a, k][t]}, {a, k}, t, 
 Method -> {NMinimize, Method -> "SimulatedAnnealing"}]

Is there a way to add constraints to FindFit such as x'[1000] == 0, x''[1000] < 0,. How do you go about doing this? Thanks!

  • 2
    $\begingroup$ Formally, you can add additional constraints to second argument of FindFit (see help). And because x[t] is modelt[a, k][t] you can write smth. like FindFit[{1000, Pi/6}, {modelt[a, k][t], modelt[a, k]'[1000]==0,modelt[a, k]''[1000]<0}, {a, k}, t, Method -> {NMinimize, Method -> "SimulatedAnnealing"}]. $\endgroup$
    – Alx
    Commented Oct 16, 2019 at 12:25
  • $\begingroup$ Hey @Alx ! Thanks for the help, you were correct in your suggestion! I will add it as a solution. $\endgroup$
    – Cameron F.
    Commented Oct 17, 2019 at 9:02
  • $\begingroup$ @Alx, I have started working on combining your solution with another popular question on FindFit but have come to a bit of a roadblock, if you have a second let me know! Here is the link to it: mathematica.stackexchange.com/questions/208054/… $\endgroup$
    – Cameron F.
    Commented Oct 17, 2019 at 9:55

1 Answer 1


As @Alx suggested in the comments, adding constraints onto the model such as modelt[a, k]'[1000]==0,modelt[a, k]''[1000]<0 was the correct method. Thanks to him!


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