I used the InterpolatingPolynomial
function to get a polynomial that meets my points.
But I noticed that there is a deviation in the final intervals.
ClearAll["Global`*"]
dados16={{10,0.37},{15,0.47},{20,0.54},{25,0.61},{30,0.70},{40,0.80},{50,0.90},{60,1.01},{70,1.10},{80,1.20},{90,1.31},{100,1.42},{110,1.53}};
B16[l_]=InterpolatingPolynomial[dados16,l]//Expand;
Plot[B16[l],{l,0,110},Epilog->{{Red,PointSize[.02],Point[dados16]}}]
What would be the best function to have a better result?
Interpolation
or you do want to have the symbolic formula of the polynomial? Can you use other types of polynomials, say, found withFindFormula
? $\endgroup$ – Anton Antonov Sep 19 '19 at 17:27