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I want to plot my function on the log-log scale. Why this code doesn't work for me? I write the following one, but nothing happens. 

ContourPlot[
Sin[3 x]+Cos[3 y]==1/2,
{x,.01 Pi,3 Pi},
{y,.01 Pi,3 Pi},
ScalingFunctions->{"Log","Log"}]
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    $\begingroup$ Looks all fine for me when I try it in my copy of version 12. What's the issue? $\endgroup$
    – Henrik Schumacher
    Aug 28, 2019 at 1:29
  • $\begingroup$ Mine is version 11. Can it be a reason for the problem? The problem is that nothing happens. No error is shown. No graph is shown. $\endgroup$
    – Mehrdad
    Aug 28, 2019 at 2:27
  • $\begingroup$ Hm. Maybe if you increase to increase PlotPoints...? $\endgroup$
    – Henrik Schumacher
    Aug 28, 2019 at 2:36
  • $\begingroup$ Code works fine with versions 11.2, 113, and 12.0 on a Mac. $\endgroup$
    – Bob Hanlon
    Aug 28, 2019 at 3:02

1 Answer 1

Reset to default
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In version <=11 try this workaround

ContourPlot[Sin[3 Exp[logx]] + Cos[3 Exp[logy]] == 1/2, {logx, Log[.01],Log[3 Pi]}, {logy, Log[0.01], Log[3 Pi]}]

enter image description here

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