# Expression manipulation

How can one write $$\frac{ad+bc}{bd}$$ in $$\frac{a}{b}+\frac{c}{d}$$ form? In other words, is there something opposite of Together[]?

Edit

My intend was to write

(8380*(x6[t] - x7[t])*(-0.130610 + Sqrt[(x6[t] - x7[t])^2 + (y6[t] - y7[t])^2]))/
Sqrt[(x6[t] - x7[t])^2 + (y6[t] - y7[t])^2]


as

8380*(x6[t] - x7[t])*(1 - 0.13061/Sqrt[(x6[t] - x7[t])^2 + (y6[t] - y7[t])^2])

• FullSimplify[(ad + bc)/(b*d)] – Fraccalo Aug 18 '19 at 13:37
• Also look at Apart as the counterpart of Together. For example, Apart[(a*d + b* c)/(b*d)]. – Tim Laska Aug 18 '19 at 14:08
• I used both these functions for the expression given in Edit. Neither of them worked. – Soumyajit Roy Aug 18 '19 at 14:56
• 8380*(x6[t]-x7[t])*FullSimplify[(-0.130610 + Sqrt[(x6[t]-x7[t])^2 + (y6[t]-y7[t])^2]) /Sqrt[(x6[t]-x7[t])^2 + (y6[t]-y7[t])^2]] instantly gives me 8380*(x6[t]-x7[t])*(1-0.13061/Sqrt[(x6[t]-x7[t])^2 + (y6[t]-y7[t])^2]) – Bill Aug 18 '19 at 15:49