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Variable x is supposed to be constant, but the program calculates for each variable x, 100 numbers of x. I want all my x variables to have the same definition, but the program constantly changes each x variable's definition.

https://1drv.ms/u/s!AqOJ6xqR2PKjglEgVfbcNx8XyKX5?e=SdAOHZ

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  • $\begingroup$ Your definition x=Table[...] creates a list called x. Please clarify what you want to calculate! $\endgroup$ – Ulrich Neumann Aug 13 '19 at 13:18
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I'm not sure I've understood your NB, but probably this is what you want:

ddQ2[x_] = \!\(\*SubsuperscriptBox[\(\[Integral]\), \(x\), \(1\)]\(z \((1 - 
z)\)*\((0.288554*\*SuperscriptBox[\((1 - \*FractionBox[\(x\), \(z\)])\), \(0.435 - 
1\)]/\*SqrtBox[FractionBox[\(x\), \(z\)]])\) \[DifferentialD]z\)\)

Then make ListPlot:

ListPlot[ddQ2[#] & /@ Table[j/100, {j, 1, 100}],PlotRange->All]

enter image description here

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  • $\begingroup$ Equivalent in InputForm. ddQ2[x_] = Integrate[ z*(1 - z)*(0.288554*((1 - x/z)^(0.435 - 1)/Sqrt[x/z])), {z, x, 1}] $\endgroup$ – Rohit Namjoshi Aug 13 '19 at 17:24
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x = Table[j/100, {j, 1, 100}];

Since x is a List, Map the integration onto the List. Since you are using inexact numbers, NIntegrate is as good as Integrate and is much faster.

{#, Integrate[z*(1 - z)*(0.288554*((1 - #/z)^(0.435 - 1)/
                Sqrt[#/z])), {z, #, 1}]} &[1/2] // AbsoluteTiming

(* {0.524199, {1/2, 0.0838901}} *)

{#, NIntegrate[z*(1 - z)*(0.288554*((1 - #/z)^(0.435 - 1)/
                Sqrt[#/z])), {z, #, 1}]} &[1/2] // AbsoluteTiming

(* {0.007069, {1/2, 0.0838901}} *)

 ddQ2 = {#, NIntegrate[z*(1 - z)*(0.288554*((1 - #/z)^(0.435 - 1)/
                 Sqrt[#/z])), {z, #, 1}]} & /@ x;

ListPlot[ddQ2, AxesLabel -> {"x", "ddQ2"}]

enter image description here

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