Solving the Schrodinger equation for a free particle gives me this output:
What does the $\psi^{(2,0)}$ mean here?
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K[1]
is a generated parameter here, but the formatting of $\psi$ doesn't seem to match? $\endgroup$ – Dan Goldwater Aug 7 '19 at 15:44D[\[Psi][x, t], {x, 2}]
$\endgroup$ – kglr Aug 7 '19 at 15:48