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I have equation E^y = x. How can I use Mathematica to solve all of "y" from the desired "x" value. For example, I want to solve for "y" from x = 0.5 , 1 , 1.5 , 2 , .... , 9.5 , 10. The solution should be (x=0.5 | y= -0.693) , (x=1 | y=0) , (x=2 | y=0.693) , ..... , (x=10 | y=2.302).

PS. Solving without algebraic technique e.g. Without taking Ln at both sides. Because the real equation is quite complicated which cannot be solved. The equation above is just an example.

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  • $\begingroup$ Do you want to run a minimization? It's not clear why you want it done without algebraic technique. Can you please explain better the context and what you are after? By the way, welcome to Mma.SE. Please follow this advice: taking the tour now, learn about asking and what's on-topic. Always include minimal working example of code and data in formatted form. By doing all this you help us to help you and likely you will inspire great answers. $\endgroup$
    – rhermans
    Jul 23, 2019 at 14:00
  • $\begingroup$ Because the real equation is quite complicated which cannot be solved. $\endgroup$
    – Ron
    Jul 23, 2019 at 14:04
  • $\begingroup$ Please edit your question and explain that there. Does it take long for your equation to evaluate? Don't make us guess the information necessary to reproduce your problem. $\endgroup$
    – rhermans
    Jul 23, 2019 at 14:06

1 Answer 1

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If you're looking for an numeric solution try

soly[x_] := Values@ NSolve[Exp[y] == x, y, Reals][[1, 1]] (*"solver"*)
Table[{x, soly[x]}, {x, 0.5, 10, .5}]
(*{{0.5, -0.693147}, {1., 0.}, {1.5, 0.405465}, {2., 0.693147}, {2.5,0.916291}, 
{3., 1.09861}, {3.5, 1.25276}, {4., 1.38629}, {4.5,1.50408}, {5., 1.60944}, 
{5.5, 1.70475}, {6., 1.79176}, {6.5,1.8718}, {7., 1.94591}, {7.5, 2.0149}, 
{8., 2.07944}, {8.5,2.14007}, {9., 2.19722}, {9.5, 2.25129}, {10., 2.30259}}*)
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  • $\begingroup$ Thank you so much. $\endgroup$
    – Ron
    Jul 23, 2019 at 14:16
  • $\begingroup$ You're welcome! $\endgroup$
    – Ulrich Neumann
    Jul 23, 2019 at 14:17

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