# Evaluating an integral symbolically

I am trying to integrate following integral symbolically via integrate command:

$$(0.09)\Bigg[1 + \Bigg\{ \int_{3t-4k-7}^{2k+7/3} (0.09) \text{exp}\Bigg(\int_{3s-4k-7}^{2k+7/3} (0.09) \text{exp}\Bigg(\int_{3u-4k-7}^{2k+7/3}(0.09)d\xi \Bigg)du\Bigg)ds\Bigg\} \Bigg]$$

but it gives a result like this:

$$0.09(1+0.06(-1.56+1.23\text{ExpIntegralEi}[1482e^{4.82k-2.43t}]$$

and I can't evaluate this expression further even if I substitute integers with $$k$$.

How can I proceed further of this expression?

Edit: Mathematica code

integral1 = \!$$\*SubsuperscriptBox[\(\[Integral]$$, $$3 u - 4 k - 7$$, $$2 k + 7/3$$]$$\((0.09)$$ \[DifferentialD]\[Xi]\)\)

integral2 = \!$$\*SubsuperscriptBox[\(\[Integral]$$, $$3 s - 4 k - 7$$, $$2 k + 7/3$$]$$\((0.09)$$ Exp[integral1] \[DifferentialD]u\)\)

integral3 = \!$$\*SubsuperscriptBox[\(\[Integral]$$, $$3 t - 4 k - 7$$, $$2 k + 7/3$$]$$\((0.09)$$ Exp[integral2] \[DifferentialD]s\)\)
$$$$

• Please paste copy&pastable Mathematica code instead of LateX. It is not fair to the people who are trying to assist to make them need to retype all your content based on some LateX code.? Jul 14, 2019 at 11:00
$Version (* "12.0.0 for Microsoft Windows (64-bit) (April 6, 2019)" *) Integrate[(9/100)*Exp[Integrate[(9/100)*Exp[Integrate[9/100, {ξ, 3*u - 4*k - 7, 2*k + 7/3}]], {u, 3*s - 4*k - 7, 2*k + 7/3}]], {s, 3*t - 4*k - 7, 2*k + 7/3}] (*ConditionalExpression[-(1/9) E^(-(E^(21/100)/3)) (ExpIntegralEi[E^(21/25)/3] - ExpIntegralEi[1/3 E^(3/100 (280 + 162 k - 81 t))]), E^(162 k - 81 t) >= 0]*) %[] /. k -> 1 /. t -> 1(*I assume for k and t *) (* -(1/9) E^(-(E^(21/100)/3)) (ExpIntegralEi[E^(21/25)/3] - ExpIntegralEi[E^(1083/100)/3]) *)  $$-\frac{1}{9} e^{-\frac{e^{21/100}}{3}} \left(\text{Ei}\left(\frac{e^{21/25}}{3}\right)-\text{Ei}\left(\frac{e^{1083/100}}{3}\right)\right)$$ • But I want to evaluate it symbolically, not numerically. Is this possible? – user66557 Jul 14, 2019 at 11:29 • @mrtkp9993. I edited the answer. Jul 14, 2019 at 11:50 • My main problem is, I can't get rid of ExpIntegralEi function. – user66557 Jul 14, 2019 at 11:53 • @mrtkp9993.You can't get rid of ExpIntegralEi function ,because is a special function like Erf,BesselJ and so on.It's impossible.You can't simplifying more,try:ExpIntegralEi // FullSimplify`,this is the final answer. Jul 14, 2019 at 12:09 • @mrtkp9993 This is like evaluating$\int_1^x\frac{1}{x}=\log x$, and asking how to remove the$\log\$; you just can't. Jul 14, 2019 at 19:24