I obtained a surface defined by $f(x,y,z) = 0$ using ContouPlot3D. How can I plot the domain of this surface in the $(x,y)$ plan? In other words I am looking for the projection of the surface onto the $(x,y)$ plan. Note that I am not trying to have the surface and its projection on the same figure like in here, only a 2d region of the domain. Thanks in advance!
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1 Answer
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If you name your plot (Graphics3D-object )
plt=ContourPlot3D[x^3 + y^2 - z^2 == 0, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}]
you can change the points to x,y (2D) and use the Graphicsstructure:
plot[[1]] /.GraphicsComplex[p_List, rest__] :>GraphicsComplex[Map[Most[#] &, p], rest];
Graphics[%]
or change the viewpoint of your 3D-Plot
Show[plot, ViewPoint -> {0, 0, Infinity}]
answered Jul 2, 2019 at 15:37
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$\begingroup$ "Comments are used to ask for clarification or to point out problems in the post. Outdated comments may get deleted." Still, I can't help writing to say thank you! $\endgroup$ Jul 2, 2019 at 18:25
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$\begingroup$ Now, could you please help me doing the same thing, i.e finding the 2d domain of a surface lying in a 3d space, but when my surface in not defined by $f(x,y,z)=0$ anymore, but rather as the intersection of a volume obtained using RegionPlot3D, called vol, with a surface obtained via ContourPlot3D, let's call it surf? $\endgroup$ Jul 5, 2019 at 13:21