Two functions both change with the same independent variable t, there is another variable represent different groups (z). how to plot y[t] versus x[t] with each group of z represented by one independent curve. See example equation below, with z as a separate integer variable that varies while t is a continuous variable. Please note I do not plan to use Manipulate function.

x[z_][t_] := z/5*Exp[-0.1*t]
y[z_][t_] := 500/(2 + x[t])
ParametricPlot[{Evaluate[x[z][t]],Evaluate[y[z][t]},{x,0,100},{z,zlist},AspectRatio -> 1]

You'll want to use Table within ParametricPlot to plot multiple curves.

There are a few issues with your code. 1) The definition of y[z][t] refers to x[t] not x[z][t]. 2) zlist isn't defined. 3) The syntax of ParametricPlot doesn't take anything like {z, zlist}.

This works:

x[z_][t_] := z/5*Exp[-0.1*t]
y[z_][t_] := 500/(2 + x[z][t])

  Evaluate[Table[{x[z][t], y[z][t]}, {z, {1, 2, 5, 10, 20}}]]
, {t, 0, 100}, AspectRatio -> 1]

Mathematica graphics

All the curves overlap, because they're all variants of y = 500/(2 + x).

  • 1
    $\begingroup$ Manipulate can help to visualize the overlap: Manipulate[ ParametricPlot[ {{x[20][t], y[20][t]}, {x[z][t], y[z][t]}}, {t, 0, 100}, PlotStyle -> {{LighterBlue, Dashed}, Red}, PlotLegends -> Placed[{20, z}, {.5, .5}], AspectRatio -> 1, PlotRange -> {{0, 4}, {80, 250}}], {z, zlist}] $\endgroup$ – Bob Hanlon May 11 at 15:28
  • $\begingroup$ This Manipulate function is really helpful. Thank you both. $\endgroup$ – Math Entry May 11 at 18:32

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