I have a system of equations all linear in one variable X with many parameters. I am trying to separate the variable in these equations by taking the pairwise resultants of one of the equation with the other ones so that the resultants are equal. E.g.


Where the equations are something like this:

eq1 = a b c X +  e/h f^5 g^2 X + 6 a^3/g k X + .... + az/h^2 X

And what I want to get are expressions A1,..An in a, b, c,.. (free of X), which are equal. However, it is running too slow and I am not getting any result. Perhaps there is another way of doing that in Mathematica?

  • 3
    $\begingroup$ This is hard to answer without concrete definitions. $\endgroup$ – Henrik Schumacher Apr 23 '19 at 10:55

I have found out that using Solve is much faster than Resultant. So if I solve each equation for X, I get equal expressions in a, b, c, etc free of X as required.

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