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I have this equation:

((a * (1 - t)^2 + 2 * d * (1 - t) * t + g * t^2) - j)^2+((b * (1 - t)^2 +
  2 * e * (1 - t) * t + h * t^2) - k)^2 +
  ((c * (1 - t)^2 + 2 * f * (1 - t) * t + i * t^2) - l)^2 == r^2

Its long and very badly writed but I count on Wolfram to simplify it. But here I have a lot of unknown while in real all variable except $t$ are known, I plan to use it in a video game so even right know I don't know $a$, $b$, $c$, ... These variable will be known at calculation.
So I want to tell Wolfram, only $t$ is unknown and obtain the result $t=a+b^2...$.

Currently I have tried solve [my equation] for $t$ and searched in the equation page but I didn't find my solution.

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closed as off-topic by Roman, Bob Hanlon, MarcoB, Henrik Schumacher, Daniel Lichtblau Apr 22 at 23:25

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This question arises due to a simple mistake such as a trivial syntax error, incorrect capitalization, spelling mistake, or other typographical error and is unlikely to help any future visitors, or else it is easily found in the documentation." – Roman, MarcoB
If this question can be reworded to fit the rules in the help center, please edit the question.

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    $\begingroup$ I'm voting to close this question as off-topic because it is Wolfram Alpha specific rather than about Mathematica. $\endgroup$ – Bob Hanlon Apr 22 at 11:57
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This will do but generates a very large solution:

Solve[((a*(1 - t)^2 + 2*d*(1 - t)*t + g*t^2) - 
  j)^2 + ((b*(1 - t)^2 + 2*e*(1 - t)*t + h*t^2) - 
  k)^2 + ((c*(1 - t)^2 + 2*f*(1 - t)*t + i*t^2) - l)^2 == r^2, t]

In fact there are four solutions given as a list in the above result. This is to be expected from a fourth-order polynomial equation.

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  • $\begingroup$ Thx but it says "Standard computation time exceeded..." will the Browser toolbar use my computer and not be limited or I have to buy pro (or optimise the request but I don't know how to do that, I'm very new with this) ? $\endgroup$ – Jorropo Apr 22 at 8:05
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    $\begingroup$ This site is about Mathematica, not about Wolfram Alpha. I assumed you were working with Mathematica, where the above code works. $\endgroup$ – Roman Apr 22 at 8:07
  • $\begingroup$ Ah ok, (I was thinking Wolfram Alpha and Mathematica to be the samethings) $\endgroup$ – Jorropo Apr 22 at 8:08

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