I would like to find all row and column pairs that contain 1 in a table. For example, the row and column pairs that contain 1 in the table are (a,b),(b,a),(b,c),(c,b),(c,d),(d,c),(d,e),and (e,d).

TableForm[Table[Abs[i - j], {i, 5}, {j, 5}], TableHeadings -> {{a, b, c, d, e}, {a, b, c, d, e}}]
table = Table[Abs[i - j], {i, 5}, {j, 5}];

rc = Position[table, 1] /. n_Integer :> {a, b, c, d, e}[[n]]

(* {{a, b}, {b, a}, {b, c}, {c, b}, {c, d}, {d, c}, {d, e}, {e, d}} *)
  • $\begingroup$ Bob: Very efficient!! ... thank you! $\endgroup$ – PRG Apr 14 at 1:55
A = Table[Abs[i - j], {i, 5}, {j, 5}];
{i, j} = Transpose[Position[A, 1]];
rowtitles = {a, b, c, d, e};
coltitles = {a, b, c, d, e};
Transpose[{rowtitles[[i]], coltitles[[j]]}]
  • $\begingroup$ Henrik: Many thanks! $\endgroup$ – PRG Apr 14 at 1:54
  • $\begingroup$ You're welcome! $\endgroup$ – Henrik Schumacher Apr 14 at 7:21

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