1
$\begingroup$

I would like to find all row and column pairs that contain 1 in a table. For example, the row and column pairs that contain 1 in the table are (a,b),(b,a),(b,c),(c,b),(c,d),(d,c),(d,e),and (e,d).

TableForm[Table[Abs[i - j], {i, 5}, {j, 5}], TableHeadings -> {{a, b, c, d, e}, {a, b, c, d, e}}]
$\endgroup$

2 Answers 2

2
$\begingroup$
table = Table[Abs[i - j], {i, 5}, {j, 5}];

rc = Position[table, 1] /. n_Integer :> {a, b, c, d, e}[[n]]

(* {{a, b}, {b, a}, {b, c}, {c, b}, {c, d}, {d, c}, {d, e}, {e, d}} *)
$\endgroup$
1
  • $\begingroup$ Bob: Very efficient!! ... thank you! $\endgroup$
    – user42700
    Apr 14, 2019 at 1:55
3
$\begingroup$
A = Table[Abs[i - j], {i, 5}, {j, 5}];
{i, j} = Transpose[Position[A, 1]];
rowtitles = {a, b, c, d, e};
coltitles = {a, b, c, d, e};
Transpose[{rowtitles[[i]], coltitles[[j]]}]
$\endgroup$
2
  • $\begingroup$ Henrik: Many thanks! $\endgroup$
    – user42700
    Apr 14, 2019 at 1:54
  • $\begingroup$ You're welcome! $\endgroup$ Apr 14, 2019 at 7:21

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.