3
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My current code is:

round = .1;
f[x_] := x + 4 - Sqrt[3 x^2 - 5]
xx = Solve[f[x] == 0, Reals];
StringForm["x=`1`", 
If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round], 
"none"]]

x=5.800000000000001`

which i want to give me an output of "x = 5.8" instead.

Any advice would be appreciated.

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2
  • $\begingroup$ StringForm["x=1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]] $\endgroup$
    – Bob Hanlon
    Mar 7, 2019 at 23:41
  • 1
    $\begingroup$ Could round exactly and then use N: N[Round[Max[xx[[All, 1, 2]]], 1/10]] $\endgroup$
    – Daniel Lichtblau
    Mar 7, 2019 at 23:42

3 Answers 3

Reset to default
5
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You could add a StandardForm wrapper:

StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]

x=5.8

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1
  • $\begingroup$ Thank you! that worked and i have no idea why, i'll read the documentation for standardForm $\endgroup$
    – Wombles
    Mar 7, 2019 at 23:40
4
$\begingroup$ 
StringForm["x=`1`", If[Length[xx] >= 1, 
  DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2], 
  "none"]]

x = 5.8

Same result with NumberForm in place of DecimalForm.

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1
  • $\begingroup$ Thank you, this worked great $\endgroup$
    – Wombles
    Mar 8, 2019 at 1:23
2
$\begingroup$ 
StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]]

x = 5.8

Round[q*10] rounds 10q to the nearest integeger.

Round[q*10]/10 rounds q to the nearest tenth.

ToString turns an expression into a string and StringJoin joins strings, both aptly named ...

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1
  • $\begingroup$ Just fixed a typo (was missing a right bracket (])). $\endgroup$
    – mjw
    Mar 8, 2019 at 3:59

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