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I need to solve the following system for the unknowns x and y.

x + b y - 3 c x^2 y - y^3 == 0
(-x/b) - y + x^3 + 3 c x y^2 == 0

where b and c are real parameters.

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1 Answer 1

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Try this

Eq1 = x + b*y - 3*c*x^2 y - y^3 == 0

Eq2 = (-x/b) - y + x^3 + 3 *c *x*y^2 == 0

Solve[{Eq1, Eq2}, {x, y}]
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  • $\begingroup$ But it is not a good method to solve this kind of systems $\endgroup$
    – Sara yaqob
    Commented Feb 8, 2019 at 12:01
  • $\begingroup$ You can get a more compact form by using the option Cubics -> False (solutions are then expressed as Root objects rather than radicals) and Simplify. Solve[{Eq1, Eq2}, {x, y}, Cubics -> False] // Simplify $\endgroup$
    – Bob Hanlon
    Commented Feb 8, 2019 at 15:52
  • $\begingroup$ What is not good about it? $\endgroup$ Commented Feb 8, 2019 at 17:19
  • $\begingroup$ Thank you dear sir $\endgroup$
    – Sara yaqob
    Commented Feb 11, 2019 at 4:35

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