I want to draw 2D curves in a 3D plot. For example, I have a function
F[x_, y_] := (3 x + y(2 + 5 y))/23
and want to plot it as shown below:
I need help with the Mathematica programing.
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$\begingroup$ Have you seen the answers to this question: mathematica.stackexchange.com/questions/1413/…? Also, check out the Linked Questions on the right side of that page. $\endgroup$– MassDefectCommented Jan 24, 2019 at 5:37
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$\begingroup$ Thank you very much @MassDefect,,, It works $\endgroup$– Shakir UllahCommented Jan 24, 2019 at 6:25
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$\begingroup$ @m_glodberg thanks for editing. $\endgroup$– Shakir UllahCommented Apr 16, 2020 at 1:55
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1 Answer
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It can be done by giving Plot3D the right options.
With[{ϵ = .05},
Plot3D[Sin[x y], {x, 0, 10}, {y, 0 - ϵ, 3 + ϵ},
PlotRangePadding -> 0.6,
PlotStyle -> Transparent,
BoundaryStyle -> None,
Boxed -> False,
AxesEdge -> {{-1, -1}, {1, -1}, {-1, -1}},
FaceGrids -> {{-1, 0, 0}, {0, 1, 0}, {0, 0, -1}},
FaceGridsStyle -> Directive[Dashed],
AxesLabel -> {"X", "Y", "Z"},
MeshFunctions -> {#2 &},
Mesh -> {Range[0, 3]},
MeshStyle -> Directive[Thickness[.009]],
Lighting -> "Neutral"]]
It takes a lot fiddling with the options to get the plot to look like your picture. Also, note the it was necessary to extend the plot range of the y-domain.
answered Jan 24, 2019 at 6:55