14
$\begingroup$

Sin[x]

Show[Plot[Sin[x], {x, 0, π}, PlotStyle -> Red, 
          PlotRange -> {{0, 2 π}, {-1, 1}}], 
     Plot[Sin[x], {x, π, 2 π}, PlotStyle -> Green, 
          PlotRange -> {{0, 2 π}, {-1, 1}}]]

Is there a simpler way of doing this? Especially, one that does not require repeating the Plot command 2 times ;)

Improve this question
$\endgroup$
22
$\begingroup$ 
 Plot[Sin[x], {x, 0, 2 π}, PlotStyle -> Thick,
 ColorFunction -> Function[{x, y}, If[x < Pi, Red, Blue]],
 ColorFunctionScaling -> False,
 PlotRange -> {{0, 2 π}, {-1, 1}}]

or

 Plot[Sin[x], {x, 0, 2 π}, PlotStyle -> Thick,
 Mesh -> {{Pi}},
 MeshShading -> {Red, Blue},
 PlotRange -> {{0, 2 π}, {-1, 1}}]

or

 Plot[{ConditionalExpression[Sin[x], 0 <= x <= Pi],
 ConditionalExpression[Sin[x], Pi <= x <= 2 Pi]}, {x, 0, 2 Pi},
 PlotStyle -> {Directive[Thick, Red], Directive[Thick, Blue]}]

enter image description here

Improve this answer
$\endgroup$
2
  • $\begingroup$ Thank you! And if I want to make the blue region dashed? I tried MeshShading -> {Red, {Blue, Dashed}} without any luck.. $\endgroup$ – Andrei Feb 4 '13 at 13:14
  • 1
    $\begingroup$ you need to use Directive: MeshShading->{Red,Directive[Blue,Dashed]} $\endgroup$ – kglr Feb 4 '13 at 13:24
1
$\begingroup$

Not a simpler way：

plt = Plot[Sin[x], {x, 0, 2 \[Pi]}];
{d, opt} = {Cases[plt, Line[x_] -> x, Infinity][[1]], plt[[2]]};
{r, b} = GatherBy[d, #[[1]] <= Pi &];
Graphics[{Thick, {Red, Line@r}, {Blue, Line@b}}, opt]
(*ListLinePlot[{r,b},PlotStyle->{{#,Red},{#,Blue}}&@Thick]*)

enter image description here

Improve this answer
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.