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Suppose have data for several x and several y(x), for example

mydata = {{11, 1.1, 2.3, 2.4}, {12, 1.3, 1.4, 1.9}, {13, 1.8, 1.7, 1.2}}
mydata // MatrixForm

So

for x=11, have y(x)= 1.1, 2.3 and 2.4

for x=12, have y(x)= 1.3, 1.4 and 1.9

for x=13, have y(x)= 1.8, 1.7 and 1.2

How to do list plot for many y(x) as function of x?

Use of 

ListPlot[mydata]

is no working.

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3 Answers 3

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mydata2 = Thread[{First@#, Rest@#}] & /@ mydata;
ListPlot[mydata2]

enter image description here

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mydata2 = Map[(mydata[[All, {1, #}]]) &, Range[2, Last@Dimensions@mydata]];
ListPlot[mydata2, Joined -> True]

enter image description here

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    $\begingroup$ Notice how your image is very similar to Mr.Wizard's image. Still, you image somehow appears to be of lower visual quality; it looks 'fuzzy' or something. Why is that? Well, this is because you saved it as a JPG image. JPG works well with photographic images, but introduces artefacts in illustrations, diagrams, screenshots, etc. For this kind of images, PNG is the ideal choice! :) $\endgroup$
    – Andreas Rejbrand
    Commented Jan 11, 2019 at 13:11
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Not applicable to all data, but in this case DataRange appears useful:

ListLinePlot[mydata\[Transpose][[2 ;;]], DataRange -> {11, 13}]

enter image description here

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