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If I have an expression where two unknown parameters and a certain range of one parameter are present then how I can get best fitted values of such two parameters by varying this range?

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You should really provide some of your attempt first, and your data would be useful. But this is how I do it.

GaussianFunction = A/Sqrt[2 \[Pi] \[Sigma]^2] Exp[-(1/2) ((x - x0)/\[Sigma])^2]

Then using NonlinearModelFit[...]

GaussianFit = NonlinearModelFit[YourData,GaussianFunction ,{\[Sigma], x0},x]

You can get the results from GaussianFit["BestFitParameters"] and plot the result as Plot[GaussianFit[x],{x,xMin,xMax}]


If you want to PLOT something rather than fit something which is what your comment suggests. Then:

GaussianFunction[A_,\[Sigma]_,x_] = A/Sqrt[2 \[Pi] \[Sigma]^2] Exp[-(1/2) ((x - x0)/\[Sigma])^2] Plot[GaussianFunction[1,1,x],{x,-10,10}] For example.

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  • $\begingroup$ M =.; GF = 1.16*10^(-5); MW = 80; mt = 172.44; x = (mt^2)/(MW^2); C1 = (x/8)*((x - 6)/(x - 1) + ((3*x + 2)/(x - 1)^2)*Log[10, x]); S1 = ((4*x - 11*x^2 + x^3)/(4*(1 - x)^2)) - (3/ 2)*(((Log[10, x])*x^3)/(1 - x)^3); λ = 0.0396; a = (C1/S1)*4; b = (2*Sqrt[2]*3.14^2)/(GFMW^2*S1); ueq = M == ((1 + (aUCos[Φ])/λ + (bU^2* Cos[2 Φ])/λ^2)^2 + ((aU Sin[Φ])/λ + (bU^2 Sin[2 Φ])/λ^2)^2)/0.8464 $\endgroup$ – Priti Nayek Jan 2 at 5:51
  • $\begingroup$ It is my data. Is it possible to draw any gaussian plot with these data? Actually I have a certain range of M and within this range I want to plot U Vs Phi and fro this graph I want to get an allowed range. $\endgroup$ – Priti Nayek Jan 2 at 5:59
  • $\begingroup$ @PritiNayek This isn't data that is usable. You should have some data that is in two column format e.g. {{x1,y1},{x2,y2},{x2,y2},...}. If you are talking about PLOTTING a Gaussian based on some known parameter values, then that is a different question and you are not fitting but just plotting. $\endgroup$ – Q.P. Jan 2 at 13:03

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