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I was working through some physics equations and came to a dead stop when I couldn't get the Derivative operator to work on equations with 2 variables. An example I striped the problem down to is below. What subtle coding principal am I missing about symbolics? I have the documentation open on the other screen and it's not exactly clear how to work with pairs as inputs to functions. I looked at everything with Fullform and didn't see anything too unexpected. Is there an explanation as to what's going on?

h[h_] := h^2 + 2 h +3
h'[u]

2+2 u

(returns as expected)

f[{x_,y_}] := x^4 + y^4
Derivative[1][f][{x,y}]    
f'[{x,y}]

f′[{x,y}]

f′[{x,y}]

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  • $\begingroup$ Better use D for total derivatives, e.g. D[f[{x, y}], {{x, y}, 1}] and D[f[{x, y}], {{x, y}, 2}]. $\endgroup$ Nov 17, 2018 at 7:37

2 Answers 2

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When a function has 2 arguments (not a single list argument), use:

f[x_, y_] := x^4 + y^4
Derivative[1, 0][f][x, y]
Derivative[0, 1][f][x, y]

4 x^3

4 y^3

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  • $\begingroup$ Ah. So I was miss reading the documentation. Thank you. $\endgroup$
    – BBirdsell
    Nov 17, 2018 at 16:30
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Here are two approaches. The first requires perhaps more tolerance for "noisy" notation. Note that I did not use a vector argument. If you must, the notation will be correspondingly "noisier".

Clear[f, x, y]
Dt[f[x, y]]
Grad[f[x, y], {x, y}].{dx, dy}
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