# differential equation - evaluate and parametric plot [closed]

I have to solve the equation in range from 0 to 7pi:

x''[t]-(1/2)(1-x[t]^2)x'[t]+x[t]=0


with boundary conditions

x(0)=1.5, x'[0]=0.


This is what I can do, but then I have a problem.

How to draw it with Evaluate in phase space? I also have to substitute the solution to the left side of differential equation and draw this formula in range of 0 < t < 7pi, on the y axis from -2 to 2. I have to use ParametricPlot and Evaluate, but don't know how. I mean, I tried to do so but it didn't work :/

## closed as off-topic by Michael E2, m_goldberg, Henrik Schumacher, José Antonio Díaz Navas, bbgodfreyNov 20 '18 at 0:40

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• Could you include your attempts with ParametricPlot in your question? – Chris K Nov 10 '18 at 19:27

eqn = x''[t] - (1/2) (1 - x[t]^2) x'[t] + x[t];
sol = NDSolveValue[{eqn == 0, x[0] == 3/2, x'[0] == 0}, x, {t, 0, 7 Pi}];

ParametricPlot[Evaluate[{t, sol[t]}], {t, 0, 7 Pi}, AspectRatio -> 1 / GoldenRatio]


Alternatively,

Plot[Evaluate @ sol[t], {t, 0, 7 Pi}]


same picture

Eq = X''[t] - (1/2) (1 - X[t]^2) X'[t] + X[t] == 0;
sol = NDSolve[{Eq, X'[0] == 0, X[0] == 3/2}, X, {t, 0, 7 Pi}];
Plot[X[t] /. sol, {t, 0, 7 Pi}]