2
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The following code gives 20 data as output.

Enter image description here

How can I make a 5*4 matrix by that data list?

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5
  • 2
    $\begingroup$ Check out Table, and don't forget to capitalize Sin and Cos. $\endgroup$
    – Chris K
    Commented Nov 4, 2018 at 15:11
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    $\begingroup$ Please post code in code blocks in the future. This is not copyable. I think this will answer all your questions: Why avoid For $\endgroup$
    – Szabolcs
    Commented Nov 4, 2018 at 15:23
  • $\begingroup$ It is edited @Szabolcs $\endgroup$
    – a b
    Commented Nov 4, 2018 at 15:42
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    $\begingroup$ Hi a-b, when Szabolcs asks for code, he means text that can be copy-pasted. The only way we can fix problems is if we can reproduce them! $\endgroup$
    – bill s
    Commented Nov 4, 2018 at 15:48
  • $\begingroup$ Please post the code as text (not an image). $\endgroup$
    – Peter Mortensen
    Commented Nov 4, 2018 at 20:58

2 Answers 2

Reset to default
5
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Here is a starting point without the For loops: 

Clear@f; 
f[i_, j_] /; OddQ[j] := c[i, j]; 
f[i_, j_] /; EvenQ[j] := s[i, j]; 

n1 = 2; 
res = Table[f[i, j], {i, -n1, n1}, {j, 1, 2*n1}]; 

(* Note MatrixForm is for presentation, not for computations *)
    res // MatrixForm

enter image description here

You can then enter your definition of c and s

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    $\begingroup$ Oh please, leave away MatrixForm. It is the cause for so many desperate questions on this forum... (still +1). $\endgroup$
    – Henrik Schumacher
    Commented Nov 4, 2018 at 16:07
  • $\begingroup$ Good point! I added a comment above to separate the calculated result from the presentation. $\endgroup$
    – FredrikD
    Commented Nov 4, 2018 at 16:09
4
$\begingroup$ 
n = 2;
Table[
 If[OddQ[j],
  Cos[2. Pi i j/(2 n + 1)],
  Sin[2. Pi i j/(2 n + 1)]
  ],
 {i, -n, n}, {j, 1, 2 n}
 ]
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1
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    $\begingroup$ +1 Or slightly shorter Table[If[OddQ[j], Cos, Sin][2. Pi i j/(2 n + 1)], {i, -n, n}, {j, 2 n}] $\endgroup$
    – Bob Hanlon
    Commented Nov 4, 2018 at 18:19

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