This is a pretty interesting problem. First, define the right-hand side.
f[θ_, μ_] := Sin[θ]/(μ + Cos[θ]);
If $|\mu|>1$, there are only the proper equilibria you noted at $\theta=n\pi$:
Plot[f[θ, 1.5], {θ, 0, 4 π}, AxesLabel -> {"θ", "θ'"}]

However if $|\mu|<1$ the denominator might equal zero, resulting in the following:
Plot[f[θ, 0.5], {θ, 0, 4 π}, AxesLabel -> {"θ", "θ'"}]

Those $\theta$ values where the denominator equals zero must also behave like stable equilibria, since $d\theta/dt>0$ below and $d\theta/dt<0$ above. I'll call them improper equilibria for lack of a better term. Any dynamicists please comment on the real name. They occur at $\theta=arccos(-\mu)$.
The following plots the proper and improper equilibria. I use linearization to assess the stability of the proper equilibria and just assume the improper ones are stable. Solid = stable, dashed = unstable.
λ[θ_?NumericQ, μ_?NumericQ] = D[f[θ, μ], θ];
eq = ContourPlot[{
ConditionalExpression[f[θ, μ], λ[θ, μ] < 0] == 0,
ConditionalExpression[f[θ, μ], λ[θ, μ] > 0] == 0,
(μ + Cos[θ]) == 0}, {μ, -2, 2},
{θ, -10^-5, 4 π + 10^-5}, ContourStyle -> {Black, {Black, Dashed}},
MaxRecursion -> 3, FrameLabel -> {μ, θ}]

Finally, add some flow arrows.
streams = VectorPlot[{0, Sign[f[θ, μ]]}, {μ, -2, 2}, {θ, 0, 4 π},
VectorMarkers -> "Arrow", VectorScale -> Tiny,
VectorPoints -> Flatten[Table[{μ, θ}, {μ, -1.8, 1.8, 0.2}, {θ, 0.25 π, 3.75 π, 0.5 π}], 1]];
Show[streams, eq, PlotRange -> {{-2, 2}, {0, 4 π}}, FrameLabel -> {μ, θ}]

Verifying the behavior of the improper equilibria with NDSolve
requires some trickery. Edit: My previous attempt at getting NDSolve
to work was wrong, so I removed it.