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I am using Mathematica 11.3.0.0, 64 bit.
Here is my code:
Graphics[Thread[Circle[{{-1, 0}, {0, 0}, {1, 0}}, {0.5, 1.0, 0.5}]]]
Here is code as it looks in a notebook:
On mouseover on , {1, 0}:
However, when I evaluate that code I am getting the right output:
Why, although is , {1, 0} colored in red, does the expression evaluate correctly? Is it a bug? Or maybe I am doing something wrong?
SyntaxInformation[Circle]
{"ArgumentsPattern" -> {Optional[{_, _}], ., Optional[{, _}]}}
That is, the first argument (if it is used) should be a list with two elements. Hence, the excess arguments are colored red by the syntax highlighter.
Is Circle[{{-1, 0}, {0, 0}, {1, 0}}, {0.5, 1.0, 0.5}] a valid input? I hope it is clear it is not.
Will Thread[Circle[{{-1, 0}, {0, 0}, {1, 0}}, {0.5, 1.0, 0.5}]] evaluate to something reasonable? It will but you don't want the FrontEnd to evaluate your code behind the hood to determine this (and of course it doesn't do this!). Consider consequences if that was something less trivial.
Related:
MapThread[Circle, {{{-1, 0}, {0, 0}, {1, 0}}, {0.5, 1.0, 0.5}}]instead. $\endgroup$SyntaxInformation[Circle]gives{"ArgumentsPattern" -> {Optional[{_, _}], _., Optional[{_, _}]}}. That is, the first argument (if it is used) should be a list of two elements. $\endgroup$