I need the ratio of x to y in this equation:

sum [n*(x/10)^n/10^(n-2)] == y from n=1 to ∞

Thank you!


closed as off-topic by Johu, Jens, Daniel Lichtblau, m_goldberg, Henrik Schumacher Sep 20 '18 at 5:29

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This question arises due to a simple mistake such as a trivial syntax error, incorrect capitalization, spelling mistake, or other typographical error and is unlikely to help any future visitors, or else it is easily found in the documentation." – Johu, Jens, Daniel Lichtblau, Henrik Schumacher
If this question can be reworded to fit the rules in the help center, please edit the question.

  • 4
    $\begingroup$ Is this about Mathamatica the software, or is it about math? Should we then forward the question to Mathematics? $\endgroup$ – Johu Sep 19 '18 at 23:23

Something like this maybe?

Solve[Sum[n (x/10)^n/10^(n-2),{n,1,\[Infinity]}]==y/.x->a y,a]/.a->x/y

{{x/y->(100 (50+y-10 Sqrt[25+y]))/y^2},{x/y->(100 (50+y+10 Sqrt[25+y]))/y^2}}

x/Sum[n (x/10)^n/10^(n - 2), {n, \[Infinity]}]
(-100 + x)^2/10000

Not the answer you're looking for? Browse other questions tagged or ask your own question.