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I am trying to make a 3D contour plot of a complicated function over a large parameter range, and I am struggling a bit to make it compute nicely and in a reasonable length of time: more specifically, if I chop the range into chunks then I can get those in a reasonable time, but if I go for the whole range then it takes ages, and I'm struggling to get a good compromise between recursion / PlotPoints / timing.

However, I can get an almost good enough plot by just joining together the different chunks of the parameter range, including them inside a single Show:

Show[{
  ContourPlot3D[
   (x - 2 Cos[z])^2 + (y - 2 Sin[z])^2
   , {x, -4, 4}, {y, -4, 4}, {z, 0, π}
   , Contours -> {1}
   , Mesh -> None
   ],
  ContourPlot3D[
   (x - 2 Cos[z])^2 + (y - 2 Sin[z])^2
   , {x, -4, 4}, {y, -4, 4}, {z, π, 2 π}
   , Contours -> {1}
   , Mesh -> None
   ]
  }
 , PlotRange -> All
 , BoxRatios -> {1, 1, 2}
 , ViewVertical -> {0, 1, 0}
 , ImageSize -> 600
 ]

Mathematica graphics

However, that still leaves a mark where the two chunks get welded.

Is it possible to do this join seamlessly?

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Using the option BoundaryStyle -> None in both ContourPlots give

enter image description here

| improve this answer | |
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  • $\begingroup$ Ah, that's where it was. Thanks =). $\endgroup$ – Emilio Pisanty Aug 9 '18 at 13:40

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