Suppose i have a function


If i evaluate condition[_,{"a","b","c"}] i get an error.

But if i manually evaluate the right hand side i get the required result.


result is

x56_ /; ! StringContainsQ[x56, {"a", "b", "c"}]
  • $\begingroup$ You could "isolate" Condition head by wrapping it with Identity: condition[pattern_, list_] := With[{x = Unique@"x"}, Identity[Condition][x : pattern, Not@StringContainsQ[x, list]]]. $\endgroup$ – jkuczm Aug 10 '18 at 9:32
  • $\begingroup$ In case of simple condition that just applies function to whole expression matched by pattern you could use PatternTest instead of Condition: condition[pattern_, list_] := pattern?(Not@*StringContainsQ[list]). $\endgroup$ – jkuczm Aug 10 '18 at 9:33

From the help for With:

You can use With[{vars},body/;cond] as the right-hand side of a transformation rule with a condition attached.

Basically, your code is that construction. Avoid having condition as the first head of the body of With:

condition[pattern_, list_] := 
  With[{x = Unique["x"]}, 
   Apply[Condition, {Pattern[x, pattern], 
     Not@StringContainsQ[x, list]}]];

condition[_, {"a", "b", "c"}]
(*x11_ /; ! StringContainsQ[x11, {"a", "b", "c"}]*)
  • 1
    $\begingroup$ You might want to prevent evaluation of Condition arguments by using holding wrapper instead of list: Condition @@ Hold[x : pattern, Not@StringContainsQ[x, list]] $\endgroup$ – jkuczm Aug 10 '18 at 9:28

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