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I have been trying to plot bifurcation diagram for $R$ vs $X$ (or $Y$) for the following problem

    tab = Table[{sol, points} = 
    Reap@NDSolveValue[{Sqrt[-1]*x'[t] == 
    B*x[t] - R*x[t]*Abs[x[t]]^2 - A*y[t], 
    Sqrt[-1]*y'[t] == 
    B*y[t] - R*y[t]*Abs[y[t]]^2 - A*x[t] /. {A -> 1, B -> -2}, 
    x[0] == 0, y[0] == 0, 
    WhenEvent[x'[t] > 0, If[t > 4, Sow[y[t]]]]}, {x, y}, {t, 0.1, 
    20}]; {R, #} & /@ 
    Union[Flatten[points], SameTest -> (Abs[#1 - #2] < .02 &)], {R, 0,
    100, 2}];
    ListPlot[Re@Flatten[tab, 1], ImageSize -> Large, AxesLabel -> {R, x}]

I get no error messages but an empty plot. Parameters are flexible so I tried several variations with parameters but didn't succeed in plotting.

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4
  • $\begingroup$ Nothing to plot, Flatten[tab, 1]={} is empty! $\endgroup$ Jul 10, 2018 at 9:24
  • 1
    $\begingroup$ You are looking for complex solutions, so the condition $x'[t]>0$ can not be fulfilled. Can be replaced by $Re[x'[t]]>0$, but in this case tab is empty too. $\endgroup$ Jul 10, 2018 at 10:48
  • $\begingroup$ Yes it keeps giving empty output when even restricting to only real solutions. $\endgroup$
    – AtoZ
    Jul 10, 2018 at 11:40
  • $\begingroup$ It has something to plot if i give it a nonzero initial condition say $x[0]=1, y[0]=0$ but then it gives errors NDSolveValue:Encountered non-numerical value for a derivative at t == 0.`. $\endgroup$
    – AtoZ
    Jul 10, 2018 at 12:10

1 Answer 1

3
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I will show the working code and the result, perhaps this is what is required.

A = 1; B = -2; tab = 
 Table[{sol, points} = 
   Reap@NDSolveValue[{Sqrt[-1]*x'[t] == 
       B*x[t] - R*x[t]*Abs[x[t]]^2 - A*y[t], 
      Sqrt[-1]*y'[t] == B*y[t] - R*y[t]*Abs[y[t]]^2 - A*x[t], 
      x[0] == 1, y[0] == 0, 
      WhenEvent[Re[x'[t]] > 0, If[t > 4, Sow[y[t]]]]}, {x, y}, {t, 
      0.1, 20}]; {R, #} & /@ 
   Union[Flatten[points], SameTest -> (Abs[#1 - #2] < .02 &)], {R, 0, 
   100, 2}];
ListPlot[Re@Flatten[tab, 1], ImageSize -> Large, AxesLabel -> {R, x}]

fig1

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  • $\begingroup$ Could you say what was the problem with OP's code? $\endgroup$
    – Chris K
    Jul 10, 2018 at 12:59
  • 2
    $\begingroup$ there are two errors: 1) two equations, and a replacement /. {A -> 1, B -> -2} is made one; 2) the condition x '[t]> 0 is used for the complex function. $\endgroup$ Jul 10, 2018 at 14:01
  • $\begingroup$ @Alex, yes it works. I have tried to modify the code with $A=10$ and $x[0]=1, y[0]=-1$ to actually see a better/clearer bifurcation behavior, It shows a plot but it is not a very clear bifurcation still. Is there a way to improve this? $\endgroup$
    – AtoZ
    Jul 11, 2018 at 6:36
  • $\begingroup$ A = 10; B = -2; tab = Table[{sol, points} = Reap@NDSolveValue[{Sqrt[-1]*x'[t] == B*x[t] - R*x[t]*Abs[x[t]]^2 - A*y[t], Sqrt[-1]*y'[t] == B*y[t] - R*y[t]*Abs[y[t]]^2 - A*x[t], x[0] == 1, y[0] == -1, WhenEvent[Re[x'[t]] > 0, If[t > 0.1, Sow[y[t]]]]}, {x, y}, {t, 0, 50}, MaxSteps -> Infinity]; {R, #} & /@ Union[Flatten[points], SameTest -> (Abs[#1 - #2] < .02 &)], {R, 0, 20, 0.01}]; ListPlot[Re@Flatten[tab, 1], AspectRatio -> .75/GoldenRatio, ImageSize -> Large, PlotStyle -> PointSize[Tiny], AxesLabel -> {R, x}] $\endgroup$
    – AtoZ
    Jul 11, 2018 at 6:46

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